Divide the string in n equal parts

Printing the string in n Equal parts

Printing the string in n equal parts:

C Program:

#include<stdio.h> #include<conio.h> int main() { char a[100]; int i,n,l,div; printf("Enter the String:"); gets(a);//get the input string printf("Enter n:"); scanf("%d",&n);//get the n value according to which the string is divided l=strlen(a);//find length div=l/n;//find equal parts if(l%n==0) { printf("%c",a[0]); for(i=1;i<strlen(a);i++) { if(i%div==0) { printf("\n"); } printf("%c",a[i]); } } else { printf("not valid length string"); } return 0; }

Output 1:

Output 2:

From the above program,

ü l=strlen(a) is used to find the length of the string, in the above output the given string is "Dandelions".

ü Length of the above mentioned string is 10.

ü n is the number of parts the string to be divided.

ü div = l/n is used to find the string to be divided and displayed.

In the above mentioned string, 

ü Dandelions need to be divided into 5(n=5) then length=10, so the equal parts of the string to be divided will be div = 10/5 =2.

So the string will be divided as 2 equal.

Output will be as,

Da nd el io ns

ü If the same string need to be divided as 2 i.e., n=2 then then equal parts will be div = 10/2 = 5.

Output will be as,

Dande lions