Printing Characters with its count in a string(Case Sensitive)

 

Printing Characters with its count in a String Using C program(Case Sensitive)

Printing Characters with its count in a string(Case Sensitive):

C Program:

#include <stdio.h> #include <string.h> int main() { char a[100]; int count,i,j; printf("Enter the String:"); gets(a);//gets the input from the user for(i=0;i<strlen(a);i++) { count=1; for(j=i+1;j<strlen(a);j++){ if(a[i]==a[j]&&a[i]!='0') { count++; a[j]='0'; } } //printing the final output if(count>1&&a[i]!='0') { printf("%c %d\n",a[i],count); } else if(a[i]!='0'&&a[i]!=' '){ printf("%c %d\n",a[i],1); } } return 0; }

Output 1:

Output 2:

From the above program,

for(j=i+1;j<strlen(a);j++){ if(a[i]==a[j]&&a[i]!='0') { count++; a[j]='0'; } }

ü a[i] is the character used for comparing.

ü a[j] is the character to be compared with a[i].

ü For every i increament, the count is initialized to 1, count gets increased whenever the character used for comparing gets repeated i.e a[i].

ü The above lines used to compare the characters in the string one by one, when the repeated character comes then its value is assigned to '0'(a[j]='0') and count is increased by 1.

ü a[i]!='  ', this condition is used to not remove the repeated blank space from the string.

if(count>1&&a[i]!='0') { printf("%c %d\n",a[i],count); }

ü The above lines used to print the count of the  repeated characters in the given string.

else if(a[i]!='0'&&a[i]!=' '){ printf("%c %d\n",a[i],1); }

ü The above line used to print the count of the non repeated character(Whose count will be 1) in the given string.

Note: printing characters with its count in a string(Case Insensitive)