Printing the pattern using C program

 

Printing the pattern Using C program

C Program:

#include<stdio.h> #include<conio.h> int main() { int num,i,j,sum=1; printf("Enter the count of rows:"); scanf("%d",&num); for(i=1;i<=num;i++) { for(j=1;j<=i;j++) { printf("%d ",sum); sum=sum+1; } printf("\n"); } return 0; }

Output:

From the above program,

ü Let num=3.

i	i<=num	j	j<=i	Print sum	Sum=sum+1	j++	Print new line		i++
1	1<=3	1	1<=1	1	Sum=1+1=2	2	Doesn’t execute
		2	2<=1 false	Doesn’t execute			Print new line		2
2	2<=3	1	1<=2	1 2	Sum=2+1=3	2	Doesn’t execute
		2	2<=2	1 2 3	Sum=3+1=4	3
		3	3<=2 false	Doesn’t execute			Print new line	3
3	3<=3	1	1<=3	1 2 3 4	Sum=4+1=5	2	Doesn’t execute
		2	2<=3	1 2 3 4 5	Sum=5+1=6	3
		3	3<=3	1 2 3 4 5 6	Sum=6+1=7	4
		4	4<=3 false	Doesn’t execute			Print new line	4
4	4<=3 false	Doesn’t execute

 

ü  i is the outer loop and j is the inner loop.

ü whenever j loop starts it's value will be assigned to 1.

ü j loop continues till the condition j<=i fails then only it moves to the outer loop i.

ü when j loop fails, new line will be printed then it moves to i loop.

ü when condition i<=num fails in i loop then the execution stops.

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